5n^2+9n-3=0

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Solution for 5n^2+9n-3=0 equation: 



5n^2+9n-3=0

a = 5; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·5·(-3)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{141}}{2*5}=\frac{-9-\sqrt{141}}{10}
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{141}}{2*5}=\frac{-9+\sqrt{141}}{10}
$

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